Ask your own question, for FREE!
Algebra 18 Online
OpenStudy (anonymous):

Please help me out ill give u a medal with answer olus explanation interested?

OpenStudy (debbieg):

Please just post a question if you have it. You don't have to "promise medals" and "entice" people to help.

OpenStudy (anonymous):

Ok just saying

OpenStudy (anonymous):

F (x) = { -x if x < or equal to 3 { 2 if x > 3 I honestly dont kno the first step whats should I do?

OpenStudy (anonymous):

@DebbieG

OpenStudy (debbieg):

What are you supposed to do? You just stated a function, not a question. ARe you supposed to graph it?

OpenStudy (anonymous):

Yes ma'am and I should Identify the domain and range

OpenStudy (anonymous):

Its different than last time

OpenStudy (debbieg):

\(y=-x\) for \(x \le 3\) \(y=2\) for \(x>3\) This is just a piecewise function. It just means that the function is defined by 2 different equations, depending on what part of the domain you are looking at. So for \(x \le 3\), you want the line \(y=-x\) (do you know how to graph that?) At the endpoint of that section of the domain, x=3, you will have a "solid dot" on this part of the graph, and the line will "end" there.

OpenStudy (debbieg):

Then on the other part of the domain, the function is given by y=2, which is just a hortizontall line at y=2. So you start that part of the function at x=3, y=2, BUT with an "open circle" at that point, (3,2), indicating that THAT point is NOT on the function (since the function is defined by the other equation for x=3, hence you have the point (3, -3) already on the graph). But then for all x>3, you have the line y=2 for the graph.

OpenStudy (debbieg):

Domain is all the x values, and since you have a definition for the function for ALL real numbers, what is the domain? Range - easiest to see if you look at your graph. Remember, range is all the possible y values. So look at what y coordinates are included somewhere on the graph of the function (remember where the function will continue towards + or - infinity).

OpenStudy (anonymous):

Thank you so much!

OpenStudy (anonymous):

Ok I got the graphing point

OpenStudy (anonymous):

I need to make a table of x and f (x)

OpenStudy (anonymous):

@DebbieG

OpenStudy (debbieg):

Yes?

OpenStudy (anonymous):

My teacher usually graphs it then she puts a table I wish I could show u how tho

OpenStudy (anonymous):

She puts x then f (x) and starts plugging in numbers

OpenStudy (debbieg):

Something like this? I did the first couple of values, can you finish it? |dw:1379463773278:dw|

OpenStudy (anonymous):

Yea but wat did u plug the numbers with to get these answers

OpenStudy (debbieg):

The function. The rule for f(x). If \(x \le3\) then y=-x if \(x >3\) then y=2 THAT'S f(x). It's a function ---- it takes an input x, and applies a "rule" to it (the equation) to give the "output", y.

OpenStudy (debbieg):

|dw:1379464385276:dw|

OpenStudy (anonymous):

I dont c the fx part

OpenStudy (debbieg):

What do you mean? You know what a function is, right? If I said: graph the function \(\Large f(x)=2x+1\) you would know how to do that?

OpenStudy (debbieg):

I mean, you're studying piecewise functions, so I've been assuming that you understand the basic concept of a function. If that's not the case you need to say so.

OpenStudy (anonymous):

Yes I do know thanx anyway

OpenStudy (debbieg):

OK, then I do not know what you mean by "I dont c the fx part". I don't know what you aren't understanding. But I see you are working with someone else on a very similar problem, so maybe just focus on that. If you understand how to do the other one, you should be able to do this one too.

OpenStudy (anonymous):

I guess so

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!