What is mono-exponential decay? (As opposed to normal exponential decay)

Question

australopithecus · Answer

it involves the exponent of a single variable

australopithecus · Answer

biexponential involves having two exponents, it is typically the sum of two exponential ones

anonymous · Answer

So does that mean that when people talk about exponential decay they're usually talking about mono-exponential decay, but they don't specify because it's implied? Or is it a totally different thing?

australopithecus · Answer

I think you are correct, tbh I just looked the definition of monoexponential up

australopithecus · Answer

It would be biexponential decay if you were calculating the decay of two different atoms or isotopes

australopithecus · Answer

I assume I have never heard of mono-exponential decay before and upon searching for it I have found very little mentioning it

anonymous · Answer

ok that makes sense. Yeah I didn't find much either! I tried looking it up but didn't have much luck. :/ 
But I think you are right so thanks!

australopithecus · Answer

http://cds.ismrm.org/ismrm-2000/PDF3/0766.pdf you could read this paper

anonymous · Answer

(It's mentioned in a pretty intense paper on neuroimaging I'm reading, so they're probably just being fussy and overly specific)

australopithecus · Answer

it might inform you on mono and bi exponential decay

australopithecus · Answer

lol yup

anonymous · Answer

Hmmm interesting thank you yeah lol actually it looks very similar to the paper I'm reading (though of course on a totally different topic) 
I'll definitely take a look at that!