"Let sin A = 12/13 with 90º≤A≤180º and tan B = -4/3 with 270º≤B≤360º. Find tan (A + B)."
Someone please show me how to do this.

Question

"Let sin A = 12/13 with 90º≤A≤180º and tan B = -4/3 with 270º≤B≤360º. Find tan (A + B)."
Someone please show me how to do this.

anonymous · Answer

Do you ko whwat sin, cos and tan look like in a triangle?

anonymous · Answer

Yes but this is for trig identities

anonymous · Answer

|dw:1379464059263:dw|

anonymous · Answer

Anyways I should say do you know the unit circle or at least what it looks like 'cause that's where I'm trying to go from this explanation.

anonymous · Answer

Yes I do mostly I just need a step by step answer

anonymous · Answer

|dw:1379464239600:dw|

anonymous · Answer

Ok this was a trig identites question, lol I sohuld've presumed that, but not taking any chances here.

 The unit circle is useful in this type of problem becuase it's giving angle measures with restrictions and unless you know it off the top of your head, you'll prob need a unit circle, now.

Step Uno:  "sin A = 12/13 with 90º≤A≤180º"
That means from this drawing that theres an angle, A, that has a sin of 12/13 and its in QII, since it has the restriction

anonymous · Answer

|dw:1379464518800:dw|