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Chemistry 19 Online
OpenStudy (anonymous):

Density: A 250-mL flask and stopper have a mass of 110.525g. A 50.0-mL sample of gasoline is pipetted into a flask, giving the total mass of 146.770g. Find the density of the gasoline.

OpenStudy (anonymous):

@genius12

OpenStudy (anonymous):

@aaronq

OpenStudy (australopithecus):

Density is just mass/volume

OpenStudy (anonymous):

Ok so would I do 146.770g divided by 250mL?

OpenStudy (australopithecus):

well you want just the mass of the compound

OpenStudy (anonymous):

Or do I subtrace 146.770g - 110.525g and then divide that by 250mL?

OpenStudy (australopithecus):

yup

OpenStudy (anonymous):

Wait for which one is yup? subtracting right? then divide?

OpenStudy (australopithecus):

think about what you are doing

OpenStudy (australopithecus):

get the mass of the gasoline and then divide it by the volume the mass of the gasoline does not include the mass of the stopper or flask

OpenStudy (anonymous):

Ok I think I understand that part. So 146.770-110.525 = 36.245 .......... 36.245/250 = .14498 Is that correct?

OpenStudy (australopithecus):

probably

OpenStudy (australopithecus):

where are you getting the 250mL from though

OpenStudy (australopithecus):

you can solve this just think

OpenStudy (anonymous):

It said the 250 was the flask -->250mL

OpenStudy (australopithecus):

reread the question

OpenStudy (anonymous):

ok ... I will try again... ok so is it 36.245g/50mL?

OpenStudy (australopithecus):

what do you think?

OpenStudy (anonymous):

It makes for sense. :) so I would get .7249g/mL as my density?

OpenStudy (australopithecus):

yes

OpenStudy (anonymous):

OMG Woah, I guess they put that statement in there to trick me. and it worked! :/ But thank you so much!

OpenStudy (australopithecus):

well when you read a question like this think about what the person is doing

OpenStudy (anonymous):

Yes I will, when you told me to reread, I did and it made much more sense. I have another question. Would you mind guiding me through it. I would like to give it a try first, then can you check it?

OpenStudy (australopithecus):

there was no trickery in this question it is all just comprehension, if you dont get something reread the question

OpenStudy (anonymous):

Its a density question

OpenStudy (australopithecus):

Sure I dont mind helping you

OpenStudy (anonymous):

Alright thanks, So this is the question. Aluminum foil is often incorrectly termed tin foil. If the density of tin is 7.28g/cm^3, what is the thickness pf a piece of tin foil that measures 5.70 by 4.25 and has a mass of 0.655g?

OpenStudy (anonymous):

So I know its asking for the thickness.

OpenStudy (anonymous):

the mass (m) = 0.655g

OpenStudy (anonymous):

oh yes, it is cm

OpenStudy (anonymous):

same here. :)

OpenStudy (australopithecus):

this is a ratio question

OpenStudy (australopithecus):

think about it you can calculate density with the variables you have for the tin foil

OpenStudy (australopithecus):

but you are missing one variable

OpenStudy (anonymous):

ok so, 7.28g/cm^3 = 0.655g/ (5.70)(4.25)(x)

OpenStudy (australopithecus):

YES!

OpenStudy (anonymous):

Thats how I would set it up right?

OpenStudy (australopithecus):

thank you for not being slow

OpenStudy (anonymous):

lol ok great!:)

OpenStudy (anonymous):

so now I will need a sec to try this on my calculator, I will tell you what I get..

OpenStudy (australopithecus):

I assume the measurements are in units cm

OpenStudy (anonymous):

yes

OpenStudy (australopithecus):

you should always include units so you can make sure they cancel out

OpenStudy (australopithecus):

because you know what units you want when you finish the question

OpenStudy (australopithecus):

so if you end up with some other units you know you did something wrong

OpenStudy (australopithecus):

Just some advice

OpenStudy (anonymous):

Ok I will keep that in mind, thank you though! :)

OpenStudy (anonymous):

Ok so I got 0.655g x 1cm^3/7.28g/cm^3 = .08997 So then .08997cm^3/(5.70 cm)(4.25 cm) =.0037??? That answer came out weird..

OpenStudy (australopithecus):

It didn't come out weird think about how thin tinfoil is

OpenStudy (australopithecus):

unless you have never seen tinfoil

OpenStudy (australopithecus):

then look it up

OpenStudy (anonymous):

lol ha.. the number I meant, so does that mean U did it sort of right?

OpenStudy (australopithecus):

what are the units for that number?

OpenStudy (anonymous):

And yes I have seen tinfoil :)

OpenStudy (anonymous):

well since it is the thickness it would be cm?

OpenStudy (australopithecus):

yup go look at some tin foil and you should be convinced that 0.0037cm x 5.70 cm x 4.25 cm is a realistic volume for a sheet of tin foil

OpenStudy (australopithecus):

that stuff is paper thin

OpenStudy (anonymous):

Ha I will ;) Well thank you for your help, you made all of this stuff so much simpler! So I am not really sure how to use this website, how do I give you an awesome medal?

OpenStudy (anonymous):

And yes it really is very thin!

OpenStudy (australopithecus):

click the blue button

OpenStudy (australopithecus):

if you want you can fan me if you want to ask me questions in the future or just use @ then type my name immediately after to ping me

OpenStudy (australopithecus):

by ask me questions I mean send me mail readily

OpenStudy (australopithecus):

to get help with somthing idk the features on tis site are pretty easy to use

OpenStudy (australopithecus):

also make sure you close the question btw so you can open new ones

OpenStudy (anonymous):

Ok that is great! I will most certainly be using that! :) Its my first chemistry course, so if you like chemistry your the person for me! I think I got the main navigation ways around the website but thanks! lol yes, that would be helpful! THANKS!

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