Question

the point (_,0) is the center of the circle (x-2)^2+y^2=16

Answer 1

i am willing to bet you can guess the answer

Answer 2

?

Answer 3

make a guess.
pick one of the numbers you are looking at.
don't pick 16

Answer 4

2?

Answer 5

you win

Answer 6

but why?

Answer 7

16 is the square of the radius, so the radius if 4

Answer 8

why is a good question

Answer 9

general form of a circle is
\[(x-\color{red}h)^2+(y-\color{blue}k)^2=r^2\] for a circle with center \((\color{red}h,\color{blue}k)\) and radius \(r\)
it comes from the distance formula

Answer 10

you have
\[(x-2)^2+(y-0)^2=4^2\] so your radius is 4, and the center is \((2,0)\)

Answer 11

ok thanks, that makes sense

Answer 12

yw