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Mathematics 11 Online
OpenStudy (anonymous):

Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of each function. y=x^2-10x+2

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (campbell_st):

for a parabola \[y = ax^2 + bx + c\] the axis of symmetry is found using \[x = \frac{-b}{2a}\] in your question a = 1 and b = -10 substitute them for the line of symmetry. the vertex is on the line of symmetry so substitute the value of x in the line of symmetry into the original equation to find the vertex

OpenStudy (anonymous):

okay thank you

OpenStudy (anonymous):

but how would I find the x-value? @campbell_st

OpenStudy (anonymous):

*y-value?

jimthompson5910 (jim_thompson5910):

once you get the x value, plug it into the equation and evaluate to get the y value

OpenStudy (anonymous):

Thank you I know I can always count on you :) @jim_thompson5910

jimthompson5910 (jim_thompson5910):

you're welcome

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