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Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of each function. y=x^2-10x+2
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@jim_thompson5910
for a parabola \[y = ax^2 + bx + c\] the axis of symmetry is found using \[x = \frac{-b}{2a}\] in your question a = 1 and b = -10 substitute them for the line of symmetry. the vertex is on the line of symmetry so substitute the value of x in the line of symmetry into the original equation to find the vertex
okay thank you
but how would I find the x-value? @campbell_st
*y-value?
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once you get the x value, plug it into the equation and evaluate to get the y value
Thank you I know I can always count on you :) @jim_thompson5910
you're welcome
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