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Mathematics 8 Online
OpenStudy (anonymous):

Can someone please help me? 5<3x-1<17

jimthompson5910 (jim_thompson5910):

first add 1 to all sides after all that is done, divide all sides by 3 to isolate x

jimthompson5910 (jim_thompson5910):

tell me what you get

OpenStudy (anonymous):

You mean add 1 to 5 and 17?

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

I got x>7 but im not totally sure if its right or not.

jimthompson5910 (jim_thompson5910):

5<3x-1<17 5+1<3x-1+1<17+1 ... add 1 to all sides 6 < 3x + 0 < 18 6 < 3x < 18 with me so far?

OpenStudy (anonymous):

Im not the best at math haha

jimthompson5910 (jim_thompson5910):

that's ok, that's what practice is for

OpenStudy (anonymous):

yeah then u divide by 3?

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

and u get 1<x<6 i added the 6 and 1 together

jimthompson5910 (jim_thompson5910):

then from 6 < 3x < 18, you divide all sides by 3 to isolate x 6 < 3x < 18 6/3 < 3x/3 < 18/3 2 < 1x < 6 2 < x < 6

jimthompson5910 (jim_thompson5910):

So 5<3x-1<17 turns into 2 < x < 6

OpenStudy (anonymous):

crap. for some odd reason i thought 3 went into 6 once haha

jimthompson5910 (jim_thompson5910):

that's ok, silly mistake

OpenStudy (anonymous):

yeah haha

OpenStudy (anonymous):

so the answer would be x<8?

jimthompson5910 (jim_thompson5910):

no the answer is 2 < x < 6

jimthompson5910 (jim_thompson5910):

it basically says in english "x is some number between 2 and 6, but it is not equal to 2 or 6"

OpenStudy (anonymous):

ohhhh i get it

jimthompson5910 (jim_thompson5910):

that's great

OpenStudy (anonymous):

Thanks :)

jimthompson5910 (jim_thompson5910):

you're welcome

OpenStudy (anonymous):

But wait how would you graph that?

jimthompson5910 (jim_thompson5910):

step 1) draw a number line step 2) plot an open circle at x = 2 on the number line step 3) plot an open circle at x = 6 on the number line step 4) shade in between the open circles on the number line

OpenStudy (anonymous):

Oh yeah. Thanks alot!

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