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Evaluate the integral: ∫dx/(sqrt((x^2)+16))
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\[\ln | x + \sqrt{ x^{2} + 16} |\]
How can I get it? I mean please explain me more than that
you know inverse hyperbolic sine function?
look at equation (1) down below http://mathworld.wolfram.com/InverseHyperbolicFunctions.html so it's wise to substitute x = sinh(u)
or just put x=tan(u) and keep simplifying and simplifying.
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First substitute x = tan(u). On solving you will get ....
\[\int\limits_{}^{} Sec (u) du\]
Which is eqaul to
\[\log_{} ( \sec(u) + \tan(u))\]
srry ...please change the substitution to x = a.tan(u)
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Now inside the log.........replace tan(u) with x/a & sec(u) with
\[\sqrt{ x ^{2} + a^{2}} \div a\]
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