Question

The bullet travels 148.5 ± 0.5 cm in 5.8 ± 0.1 ms (1 cm = 0.01 m ,1 ms =10−3s). What is the average speed of the bullet in m/s?

Answer 1

\(\large \text{Average speed} = \frac{\text{distance travelled}}{\text{time taken}} \)

Answer 2

\(\large \text{Average speed} = \frac{148.5 \pm 0.5 cm}{5.8 \pm 0.1 ms} \)

Answer 3

\(\large \text{Average speed} = \frac{148.5 }{5.8 } \pm \delta S \)

Answer 4

\(δS\) is the uncertainty in speed.
to get this, you must find the relative uncertainties of distance and time, and add them