Question

If B=√3.a²/4 solve for 'a' and find the value of 'a' if B=16√3 ?

Answer 1

a=8

Answer 2

@Addu5221 can you explain step by step procedure

Answer 3

\[16\sqrt{3}=\frac{ a ^{2}\sqrt{3} }{ 4 }|*4\]
\[64\sqrt{3}=\sqrt{3}a ^{2}|:\sqrt{3}\
\[a ^{2}=64\]
\[a=+/-8\]

Answer 4

Do you understand how I did it?

Answer 5

its simple we have two values of B so they are equal so √3.a²/4=16√3 then a^2=4(16sqrt3)/sqrt3
a^2=64 then a=+8 or a=-8 since square of both - and + is +

Answer 6

now i understood thank you so much

Answer 7

ur welcome