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use divergence test to show series diverges (1 + 1/k ) to the power of k
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we can write the series as\[\sum_{k = 1}^{\infty} \left(1 + \frac{1}{k} \right)^k\]then we get\[u_k =\left(1 + \frac{1}{k} \right)^k\]to apply the div. test, first evaluate \[\lim_{k \rightarrow \infty} u_k\]
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