Question

evauluate the limit as x->infinity x+(x^2+3x-1)^/4x+5

Answer 1

You wrote (x^2 +3x-1)^ but you did not write any number after ^........are you missing something?

Answer 2

Actually the whole polynom is ^2 sorry forgot the 2*

Answer 3

evauluate the limit as x->infinity x+(x^2+3x-1)^2/4x+5 it goes like this

Answer 4

Expand the numerator alone and tell me.......Ask if you have any problem doing that

Answer 5

actually i wanna have the solution of this kind of limit , not just the short answer i mean step by step, i can try to draw it if u have troubles understand the limit ..

Answer 6

I understand the question........i am trying you to work out the answer on your own

Answer 7

actually i do have an idea

Answer 8

oh this is different frm what you wrote b4

Answer 9

by factorising the x inside the Decreased Square

Answer 10

Anyway........what's your idea?

Answer 11

yeah this one is the limit , the drawn one , because i didnt knew how to write it

Answer 12

k.......whenever we have the questions of this sort involving numerator and denominator........we first find the highest power of x in the question and divide both the numerator and denominator by that

Answer 13

Factorising the x^2 inside the Decreased Square both 3x and -1 goes 0 and we get 2x/4x+5 , then 5 goes 0 by dividing 5 with x and we get 2x/4x = 1/2

Answer 14

what is the highest power of x here

Answer 15

2?

Answer 16

Nope x^2 is under square root sign...........So highest power is 1

Answer 17

Let us divide both numerator and denominator by x.....

Answer 18

so do we have to factorise the highest power of x? right? to get it out of root square?

Answer 19

factorise inside root square?

Answer 20

Nope factorization is not needed here

Answer 21

How can we devide nomerator? Because there is x+(....) shouldnt we simplify it first?
idk how this works

Answer 22

\[\frac{ x + \sqrt{(x^2 + 3x -1)}\ }{ 4x +5 }\]
\[\frac{ x/x + \sqrt{(x^2/x^2 + 3x /x^2-1/x^2)}\ }{ 4x/x+5 }\]

Answer 23

Is this the question or .......is it x +( num/den)

Answer 24

no the question is right as u wrote it

Answer 25

The answer should be 1/2 final answer : lim x->infinity = 1/2 but i should only know the way

Answer 26

are you sure we are able to divide x/x+(x2/x2+3x/x2−1/x2)/ 4x/x+5

Answer 27

it goes 1+0 / 4x+5

Answer 28

It gets you (1 + 0 )/4 = 1/4

Answer 29

yea it must be 1/2 the book i found this limit got the right answer and its 1/2 the short answer

Answer 30

Maybe we need to factorize inside

Answer 31

to get 2+0 /4 = 1/2

Answer 32

Sry.........it gives you (1+1)/4 = 2/4

Answer 33

check under the square root you get : (1+0+0) when you apply x->infinity

Answer 34

Oh yes i see

Answer 35

x2/x2 = 1

Answer 36

x/x =1
x^2/x^2 =1
3x/x^2 = 3/x = 0 (when x->infinity)
1/x^2 = 0 (when x->infinity)
4x/x =4
and 5/x^2 =0 (when x->infinity)

Answer 37

so you get ( 1+1 )/4 = 1/2

Answer 38

yep thanks , one more question why 5 get divided by x^2? and not by x?

Answer 39

sry.......my mistake 5 gets divided by x and NOT x^2

Answer 40

yeap no problems thanks alot for this quite helpfull answer

Answer 41

you are welcome