I'm stuck at the ICE table.

Calculate the pH of a solution prepared by mixing 300 mL of 0.25 M sodium hydrogen ascorbate and 150 mL of 0.2 M HCl plus water to a final volume of one liter. The ka of ascorbic acid is 5 x 10^(-5)..

Question

I'm stuck at the ICE table.   

Calculate the pH of a solution prepared by mixing 300 mL of 0.25 M sodium hydrogen ascorbate and 150 mL of 0.2 M HCl plus water to a final volume of one liter.  The ka of ascorbic acid is 5 x 10^(-5)..

anonymous · Answer

pH =  pKa + log [A-]/[HA-]
pH= 4.3   --> I did pKa = -logKa for this..
pH= 4.3+log [.075]/[.030]

anonymous · Answer

for the "I"  I have : HA: 0.030; H+: 0; A-: 0.075

anonymous · Answer

I don't understand the rest of what to do..