Find the constant of variation for the relation, and use it to write an equation for the statement. Then solve the equation. If y varies directly as x, and y = 6 when x = 7, find y when x=5.
something varies directly to something else, usually means \(\bf \textit{something} = n \times \textit{something else} \implies y = n \times x\) so, what's the "constant of variation" \(\bf \text{n}\) ? we dunno but we do know that, when x = 7, y = 6 so let's use that in our equation \(\bf y = n \times x \implies 6 = n \times 7\) solve for "n", to find the \(\bf \text{contant}\) of variation
ahem \(\bf \text{constant}\) rather =)
so n=6/7
what is a statement of a triangle inequality theorem?
yes, so now that you know that, use that in the equation, to find "y" when x = 5 so, x = 5, what's "y"?, well \(\bf y = n \times x \implies y = \cfrac{6}{7}\times 5\)
Solve y = kx for k when y=6 and x=7.\[y=\frac{6 x}{7} \] find y when x=5
y=30/7
thank you guys!
np
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