Question

how to graph inequalities: how can you solve inequalities by the method dotted line and solid line positive or negative and shading the region.... im confused

Answer 1

medals will be be awarded..

Answer 2

also please dont use any tables

Answer 3

\[< and > \]
should be dotted lines.
\[\le and \ge\]
Should be solid lines.
Tables are one of the easiest ways to do it.

Answer 4

thank you so much but do you know if the slope is postivie or negative should i shade above or under to find that region

Answer 5

Well if the equation is
say y<-mx+b the slope is neg if it's just y<mx+b than the slope is pos.

Answer 6

wait i mean about the shading thing when you have 2 equations

Answer 7

and the position of the line when the slope is either positive or negative

Answer 8

Give me an example

Answer 9

such as y<3x+5

Answer 10

help..

Answer 11

Do you know how to graph a normal equation?

Answer 12

this needs to be done by hand and simple its solved with 2 inequalities

Answer 13

thanks though and yes

Answer 14

Well to determine which side is shaded you plug in any point and if it's true then that side is to be shaded if it's not true then shade the other side.

Answer 15

its just supposed to be regional where you shade not exact... thats why i asked when its positive or negative is the line supposed to be slanted to the right or left

Answer 16

pos to the right
neg to the left

Answer 17

ok thanks so much for your help

Answer 18

No problem if you'd like to see a 'hand written' one I could graph one by hand virtually.

Answer 19

sure

Answer 20

make sure this has 2 equations

Answer 21

i mean inequalities

Answer 22

Well give me an example of what you're looking for.

Answer 23

https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=1&ved=0CCsQFjAA&url=http%3A%2F%2Fwww.wikihow.com%2FGraph-Inequalities&ei=Dyc6Uo74AeOT2QW1oIGgCg&usg=AFQjCNEmBEL-Wcc9byWx5ybeza53CmbLPQ&bvm=bv.52288139,d.b2I

Answer 24

\[y \ge x+and 3y <-6x+6\]

Answer 25

thanks @jonjenkins7653

Answer 26

no prob

Answer 27

im sorry the first inquality is y is greater than or equal to x+2

Answer 28

\[y \ge x+2\] is the same as graphing y=x+2
The start at 2 and go up 1 over (to the right) 1
\[3y < -6x+6\]
You must first get the y by itself by dividing by 3 which you end up getting
\[y < -2x + 2\]
So to graph it start at 2 and go Down 2 over (to the right)1
Just a sec while I graph just the lines.

Answer 29

ok

Answer 30

So here is just the lines graphed I used virtual graph paper to graph these lines.
Blue is \[y \ge x+2\]
Orange is \[y<-2x+2\]

Answer 31

all right so far so good but arent you going to shade above or below the line to see what regions they cross at

Answer 32

Now for the shading.
Take the first inequality
\[y \ge x+2\]
And plug in (0,0) for the x and y this helps you determine which side to shade.
\[0 \ge 0+2\]
\[0 \ge 2\]
That is not true so don't shade the half the has the point (0,0)

Answer 33

so youre saying if something is not true you dont shade?

Answer 34

Then you don't shade that half.

Answer 35

ok thanks so much for your time and effort thanks for helping

Answer 36

;)

Answer 37

Here is the final graph.