Question

How do I graph 3 > or equal to x - 3y? Please help me out!!!

Answer 1

Well you have to get y on one side by itself so
\[3 \ge x-3y\]
Subtract x on both sides
\[-x +3 \ge -3y\]
Then divide by -3 on both sides.
When you divide by a negative you flip the sign so in the case it goes from greater than or equal to to less then or equal to.
\[\frac{ 1 }{ 3 }x -1 \le y\]
It could also be written like this.
\[y \ge \frac{ 1 }{ 3 }x -1\]

Answer 2

You can use this site to graph.
http://www.garrettbartley.com/graphpaper.html

Answer 3

Thanx but can u show me how to do it?

Answer 4

To determine which half to shade you just plug in a point.
I'm going to use (0,0)
\[0 \ge \frac{ 1 }{ 3 }(0)-1\]
\[0 \ge 0 -1\]
\[0 \ge -1\]
Since this is true shade the half that has the point (0,0)

Answer 5

What are the x and y I mean wat are the points?

Answer 6

Like the x and y intercepts?

Answer 7

Yes

Answer 8

The the y-int is given to you in the inequality
you have y "=" mx+b
where b is the y-int
So you y-int is -1
So where does the line hit the x-axis? (The x-axis is the horizontal black line)

Answer 9

No clue

Answer 10

Help?

Answer 11

Just look at my attachment and look where the orange line hits the black horizontal line?

Answer 12

3

Answer 13

Yepp.

Answer 14

Yaaay!

Answer 15

I think I got how to do it byt y did u do it as slope intercept form? Y didnt u do it normally

Answer 16

That is normally. That's how you graph.

Answer 17

K thanx