Question

-(-x)^3-x^3 :c

Answer 1

\[-(-x)^3-x^3=+x^3-x^3=0\]

Answer 2

Don't give away answers, John.

Answer 3

Yeh, that wasn't really much help.. but.. whatever I guess .-.

Answer 4

I can explain it for you if you want?

Answer 5

please?

Answer 6

Let's wait and see what John has to say for himself..

Answer 7

Sorry, I think it was self explained. My fault. When you calculate
\[(-x)^3\]You can calculate it, for example, doing the expansion,
\[(-x)^3=(-x)(-x)(-x)\]I think you know the multiplication rule for signs, so,
\[(-x)(-x)=+x^2\]Using
\[(-1)(-1)=+1\] and
\[x\cdot x=x^1\cdot x^1=x^{1+1}=x^2\]So now, you have,
\[(-x)^3=(-x)(-x)(-x)=+x^2(-x)\]Now you use,
\[(+1)(-1)=-1\]Multiplication of opposite signs is a minus sign, and,
\[x^2\cdot x=x^2\cdot x^1=x^3\]So you have,
\[(-x)^3=(-x)(-x)(-x)=+x^2(-x)=-x^3\]Return to the original equation and you have,
\[-(-x)^3+x^3=-(-x^3)+x^3\]But, using
\[(-1)(-1)=+1\]You have,
\[+x^3-x^3=0\]
Hope it helps.

Answer 8

Please @Luigi0210 , complete any step as you wish. ;)

Answer 9

Nice job, John.