Question

Solve the following system of equations using elimination:
6x - 5y = 3
4x - 36y = 100


A. (-3, -2)
B. (-2, -3)
C. (-2, 3)
D. (2, 3)

Answer 1

@abb0t

Answer 2

Ok, let's start by naming them equation 1, and equation 2. yes?

Answer 3

yes

Answer 4

The goal here is to rearrage one of them so you can substitute into the other.
If you rearrange eqation 1 to substitue say...into \(x\). you can proceed like this: x = \(\sf \color{red}{\frac{1}{2}+\frac{5}{6}y}\)

Answer 5

Now, notice how you have x = some function. Yes?

Answer 6

yess I do

Answer 7

Substitute THAT function in \(\sf \color{red}{red}\) into \(x\) on equation 2!
You will notice that you have a function in terms of oNLY y!
So you have: 4(\(\sf \color{red}{\frac{5}{6}y+\frac{1}{2}}\))-36y=100

Answer 8

Now, distribute the \(\sf \color{red}{4}\) into the parenthesis and solve for \(\sf \color{blue}{y}\)!! Then when you have a value for y, you can plug in that value into equation 1, and solve for \(x\)!

and you're done.
Then you have two values for x, and y!.
You can check if they are correct by plugging those values into ANY of the two equations. You should get 3, OR 100 if you plug those values in for x, or y.

Answer 9

@abb0t , you better get this one right

Answer 10

by the way, nice hair

Answer 11

you should come over and comb it sometime @Luis_Rivera

Answer 12

lol, no thanks, let nincomb do it

Answer 13

hahaha so is I D?

Answer 14

is it? @Luis_Rivera @abb0t

Answer 15

2

Answer 16

Does: 6(\(\sf\color{red}{2}\))-5(\(\sf\color{red}{3}\))=3???

Answer 17

-3

Answer 18

Yes. And does \(\sf\color{red}{-3}\) = 3?

Answer 19

get to the point!

Answer 20

no?..

Answer 21

Your answer is B!

Answer 22

oh yeaa! thanks!

Answer 23

yes @cenaida , the girl with the red hair is correct

Answer 24

hahaa lol