Question

find the inverse of f^-1(x)

Answer 1

f(x)=2x-4/5x+6

Answer 2

solve for \(\sf \color{red}{x}\) in terms of \(\sf \color{orange}{y}\)

Answer 3

so would that be x=2y-4/5y+6

Answer 4

Yessir.

Answer 5

is that the final answer? would you be able to assist me with one more, f(x)=3−ln5x+20

Answer 6

What?! Where did you get natural log from?!?!?!

Answer 7

And no, that is not the asnwer. You need to SOLVE for \(\sf \color{red}{x}\)!

Answer 8

that is a second problem i need assistance with

Answer 9

i am not sure how to complete solving for x
for the first one

Answer 10

Well, get rid of the demonimator first. Multiply both sides by \(\sf \color{red}{5y+6}\)

Answer 11

okay so your solution is x=10y^2-8y-24

Answer 12

You get: x(5x+6)=2y-4
Now, distribute the \(\sf \color{blue}{x}\) across the parenthesis.
5xy+6x=2y-4

Next, group like terms together. So subtract 2y from both sides:
5xy-2y+6=-4

subtract by 6 to both sides:
5xy-2y = -10

factor out the \(\sf \color{orange}{y}\): y(5x-2)=-10
and divide to isolate y!
the end.

Answer 13

Does that make sense?

Answer 14

Yes! So Y=-10/5x-2

Answer 15

Thank you so much!! Superb answer

Answer 16

Correct. Best of luck!

Answer 17

Thank you. Would you be able to assist me with finding the inverse of f(x)=\[\sqrt{3x+5}\]

I understand i must substitute all of the x's for y's
so...x= \[\sqrt{3y+5}\]

so x^2 = 3y+5? Is that where i would move on too? Im not sure where to go from there