A trapezoid is drawn on a grid with vertices at P(-5, 7), Q(-2, 7), R(2, 3), and S(-8, 3) . Trapezoid UVWX will be drawn similar to Trapezoid PQRS with side PQ corresponding to side UV. The point (-2, -1) will be the location of vertex U and point (7, -1) will be the location of point V. What will be the coordinates of vertex X? Show all your work or explain your reasoning.
this is as far as i got To find the vertex for X you must use the proportion UV/PQ=UX/PS. That amounts to 9/3 = 15/5. 9/3 and 15/5 equal 3 so the scale factor is 3:1.
@ganeshie8
you there isuri
*suru
***[ISURU]*** can you help me
im here
You said, you have scale factor of 3:1. Therefore, you can then find the dimensions of the other sides of the trapezoid UVWX with traperzoid PQRS as reference.
-24,9
May I see your solution?
-8 * 3=-24 and 3*3=9
what is -24,9 ?
X
is my answer right??????
I'm not sure with your solution because this wouldn't be that easy. How did you get the distance UV and PQ? May I know?
distance formula
did you already find the distance PQ and RS?
no
I think you need to find first the distance of WX using the scale ratio of 3 which must be based from the distance of RS and you can find RS using distance formula, right?
i guess
Are you done doing it now?
RS is 10
Then WX is?
i dont know because X is unknown
isn't it that you can use the relation of similar figures right? because it is written in the problem that those trapezoids are similar.
right
So WX is now then?
i really dont know
You said the the scale ratio of UVWX to PQRS is 3:1. Therefore, if RS = 10, WX = 30. You get the point?
so the lengths are just mmultiplied by 3
Yes. :) Can you find too the distance of XU?
@JackJones
how would you do that
Find PS and multiply it by 3. :)
PS is 5 so 15
Yes. Now you can use system of equality to solve for the coordinates of X using the computed distance and the distance formula for WX and UX.
could you do that part for me plz
ganshie plz help
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