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Explain why f(x)=ln(cos x) is continuous. Then find lim x->1 ln(cosx)
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\[\lim_{x \rightarrow 1}\ln(cosx)\]
f(x) = ln(cos(x)) is not continuous in any general sense. Do you mean continuous AT x = 1?
yeah, first explain how you can make it continuous, and then solve the limit as x approaches 1
I see. One might try h(x) = ln(|cos(x)|). That's continuous. The logarithm can't handle negative values.
doing the absolute?
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can u do this?|dw:1379561931537:dw|
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