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Mathematics 24 Online
OpenStudy (anonymous):

Explain why f(x)=ln(cos x) is continuous. Then find lim x->1 ln(cosx)

OpenStudy (anonymous):

\[\lim_{x \rightarrow 1}\ln(cosx)\]

OpenStudy (tkhunny):

f(x) = ln(cos(x)) is not continuous in any general sense. Do you mean continuous AT x = 1?

OpenStudy (anonymous):

yeah, first explain how you can make it continuous, and then solve the limit as x approaches 1

OpenStudy (tkhunny):

I see. One might try h(x) = ln(|cos(x)|). That's continuous. The logarithm can't handle negative values.

OpenStudy (anonymous):

doing the absolute?

OpenStudy (anonymous):

can u do this?|dw:1379561931537:dw|

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