Question

There are two different compounds of sulfur and fluorine.
In SF6, the mass of fluorine per gram of sulfur is 3.55 g F/g S.
In the other compound, SFX, the mass of fluorine per gram of sulfur is 1.18 g F/g S.
What is the value of X for the second compound?
Express your answer as an integer.

Answer 1

hi,
in 1 mole of SF6
there r 1 mole of Sulfur for 6 moles of fluorine
and according to data given
there should be
1 g of Sulfur for 3.55 g of fluorine

so from that data we can build a relationship
1 M of S --------> 6 M of F
1 g of S -------- > 3.55 g of F
the formed relation ships are directly proportional to each other
we can made the equal by dividing the 2 relationships
1 M (S) / 1 g (S) = 6 M (F) / 3.55 g (F) ----------(1)

let's move to the next one
In one mole of SFx
there r 1 mole of S for x moles of F

From the data given,
there r 1 g of S for 1.18 g of F

Now we can build 2 relationships for the second scenario tooo
1 M of S --------> x M of F
1 g of S -------- > 1.18 g of F

by dividing the 2 relationships again
1 M (S) / 1 g (S) = x M (F) / 1.18 g (F) ----------(2)

in (1) and (2) the right hand sides r equal
so
6 M (F) / 3.55 g (F) = x M (F) / 1.18 g (F)

Now u can solve this and get the answer to the nearest whole number.

Hope this will help u out !