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Solve the equation of logarithm.
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\[\log _{7} \sqrt{7}=x\]
it can also written as {log 7 (7)}/2 and log 7 (7) is 1 so x=1/2
It's also the same as \[7^x = 7^{1/2}\] Now can you solve for x?
Thanks guys. but it would helpful if you show the second step please.
Actually, the answer is already there. Since they have the same base, you can therefore conclude that the exponent x in the left is equal to the exponent at the right. :)
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