Question

2/h-7=12/5h-2h+3
HELP !!! PLZ

Answer 1

HELLP !!! PLZ

Answer 2

hello

Answer 3

Is that what you mean? \[\frac{ 2 }{ h-7 } = \frac{ 12 }{ 5h } - 2h+3\]

Answer 4

no its \[\frac{ 2 }{ 5 }h - 7 = \frac{ 12 }{ 5 }h - 2h + 3\]

Answer 5

You can multiply the whole equation by 5 so that it will be cancelled. After that is the time to solve for h. :) You follow?

Answer 6

no srry can u do it step by step plz :D

Answer 7

Let me start with what I've said
It will appear like this
\[5[\frac{ 2h }{ 5 }-7 = \frac{ 12h }{ 5 } - 2h +3]\]

Answer 8

ok

Answer 9

wait

Answer 10

Do you have idea now?

Answer 11

its not \[\frac{ 2h }{ 5 } its \frac{ 2 }{ 5 }h\]

Answer 12

Don't worry, they are just the same. :)
Do you know what to do next?

Answer 13

oh :D

Answer 14

Then distributing the 5 will cancel the denominator.
And this will happen next
2h - 7(5) = 12h - 2h (5) + 3(5)
just solve for h and that's it :)

Answer 15

can u slove it i dont get

Answer 16

2h - 35 = 12h - 10h +15
So, do you know how to continue it?

Answer 17

subtract 15 from bot sides then what

Answer 18

Wait, do you know something about axioms? Or transpositions?

Answer 19

what ?

Answer 20

nevermind.
i think it's better if you isolate first the variable against the constants.

Answer 21

Do you know it?