(3x^2a-4y^az^3a)^2 simplified?

Question

kewlgeek555 · Answer

Okay, first you ahve to combine like terms.

kewlgeek555 · Answer

Hold on.

kewlgeek555 · Answer

Do you know how to combine like terms?

anonymous · Answer

not so sure? its algbra 2.

kewlgeek555 · Answer

Oh - no wonder.  I am like trying to figure this out and the exponents are confusing me.  Its that I am in Algebra I.  I know how to do it with out exponents.  Hold on.

kewlgeek555 · Answer

Is this what you are asking?:$$(3x ^{2}a-4y ^{a}z ^{3}a)^{2}$$

kewlgeek555 · Answer

If so, $$9a ^{2}x ^{4}-24a ^{2}x ^{2}y ^{a}2^{3}+16a ^{2}y ^{2a}5^{6}$$No, that sounds wrong.  I an sorry.  I don't really know.  Hopefully @PFEH.1999 @campbell_st @Firejay5 @savannaxx_ can help you, I am not sure.  Sorry.

anonymous · Answer

did @kewlgeek555 rewrite the problem right?

campbell_st · Answer

you are basically expanding a perfect square

$$(a -b)^2 = a^2 -2ab + b^2$$

in your question 

$$a = 2x^{2a}$$

and 

$$b = 4y^az^{3a}$$

you will need to use the index law for power of a power

$$(x^a)^b = x^{a \times b}$$

the power operates on every part of the term 

as well as the law for multiplying the same base

$$x^a \times x^b = x^{a + b}$$

hope this helps...