Consider the following reaction: SO2Cl2(g)⇌SO2(g)+Cl2(g) A reaction mixture is made containing an initial [SO2Cl2] of 2.2×10−2M . At equilibrium, [Cl2]= 1.3×10−2M . Calculate the value of the equilibrium constant (Kc).
Can you write the expression for Kc?
Kc=[SO2][Cl2]/[SO2Cl2]
@harbinjolene can you solve that now or do you want help
I still can't seem to figure it out. I don't know what the values are for the concentrations.
make an ice table
\[Kc= \frac{ (1.3 \times 10 ^{-2}) (1.3 \times 10^{-2}) }{ (0.9 \times 10^{-2}) }\]
Since the molar ratio of Cl2 and SOCl2 is 1:1, you will use the equilibrium concentration as it is given. However, the initial concentration of SO2Cl2 is given. To find the equilibrium concentration, you must subtract (1.3 x 10^-3) from (2.2 x 10^-3).
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