Question

Simplify i to the eighteenth power.

Answer 1

\[i^1 = \sqrt{-1}\]\[i^2 = -1\]\[i^3 = -\sqrt{-1}\]\[i^4 = 1\]notice that at this point it repeats itself\[i^5 = \sqrt{-1}= i^{4n+1}\]\[i^6 = -1 = i^{4n + 2}\]\[i^7 = -\sqrt{-1} = i^{4n + 3}\]\[i^8 = 1 = i^{4n}\]

notice that 18 = 4n + 2 for n = 4

Answer 2

yes

Answer 3

A. 1
B. -1
C. i
D. -i

Answer 4

b

Answer 5

ya. its b. 18 is a "4n + 2"

Answer 6

thank you :)

Answer 7

@divu.mkr thank you for helping too :)

Answer 8

no prob @miryluslinares