Ask your own question, for FREE!
Trigonometry 8 Online
OpenStudy (anonymous):

How do you simplify a trigonometric expression?

OpenStudy (anonymous):

depends..do you have a question?

OpenStudy (anonymous):

no this is just what the question said that I have to answer ? ;/ It says I can provide examples and what Not

OpenStudy (anonymous):

few tricks and formulas ;)

OpenStudy (jdoe0001):

well, you use the "trigonometry identities" like -> http://www.mathwords.com/t/trig_identities.htm

OpenStudy (anonymous):

how would you word this into like 4 or 5 sentences @jdoe0001

OpenStudy (jdoe0001):

it'd be easier if you give us one, so you can see the simplification, and thus you'd write it down :)

OpenStudy (anonymous):

give an example?

OpenStudy (jdoe0001):

ok.... ahemm... let's see say , ok, gimme one sec

OpenStudy (jdoe0001):

\(\bf \textit{let us simplify, say } \quad \cfrac{sin(\theta)}{cos(\theta)}+\cfrac{cos(\theta)}{sin(\theta)}\\\quad \\ \cfrac{sin(\theta)}{cos(\theta)}+\cfrac{cos(\theta)}{sin(\theta)} \implies \cfrac{sin(\theta)sin(\theta) + cos(\theta)cos(\theta)}{cos(\theta)sin(\theta)}\\ \implies \cfrac{sin^2(\theta) + cos^2(\theta)}{cos(\theta)sin(\theta)}\\\quad \\ \textit{if you look at your trig identities}\quad sin^2(\theta) + cos^2(\theta) = 1\\ \cfrac{sin^2(\theta) + cos^2(\theta)}{cos(\theta)sin(\theta)} \implies \cfrac{1}{cos(\theta)sin(\theta)}\\ \textit{recall that }\quad sec(\theta) = \cfrac{1}{cos(\theta)} \qquad csc(\theta) = \cfrac{1}{sin(\theta)}\\\quad \\\quad\\ \cfrac{1}{cos(\theta)sin(\theta)} \implies \cfrac{1}{cos(\theta)} \cdot \cfrac{1}{sin(\theta)} \implies sec(\theta)csc(\theta) \)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!