how do i do this???? write as a single fraction
-1 +4c-9d/6c - 5c-4d/8c

Question

how do i do this???? write as a single fraction 
-1 +4c-9d/6c - 5c-4d/8c

anonymous · Answer

/ = divided by

tkhunny · Answer

It would help to clarify exactly what you have written.  What I see is this:

$-1 + 4c - \dfrac{9d}{6c} - 5c - \dfrac{4d}{8c}$

If this is not what you intended, please use more parentheses to clarify intent.  Remember your Order of Operations.

anonymous · Answer

-1 + (4c-9d/6c) (5c-4d/8c)

anonymous · Answer

oops I meant minus between the two parenthesis not multiply

anonymous · Answer

-1 + (4c-9d/6c) - (5c-4d/8c)

tkhunny · Answer

This, then: $-1 + \left(4c - \dfrac{9d}{6c}\right) - \left(5c - \dfrac{4d}{8c}\right)$

anonymous · Answer

no 4c-9d is the top of the fraction and 6c is the bottom of the fraction

anonymous · Answer

5c-4d top of fraction and 8c bottom of fraction

tkhunny · Answer

You have forgotten your Order of Operations, haven't you?

-1 + (4c-9d)/6c - (5c-4d)/8c = $-1 + \dfrac{4c-9d}{6c} - \dfrac{5c-4d}{8c}$

Are we close, yet?

anonymous · Answer

yes! that is it

tkhunny · Answer

What is the least common denominator?

anonymous · Answer

1?

tkhunny · Answer

Back up.  When adding these, how might one proceed?

$\dfrac{1}{8} + \dfrac{1}{6}$

Common denominator?

anonymous · Answer

24?

tkhunny · Answer

Okay, how about these: $1 + \dfrac{1}{3} + \dfrac{1}{4}$

anonymous · Answer

12?

tkhunny · Answer

Good.  Please add those three for me.

anonymous · Answer

3/24?

tkhunny · Answer

??  How did you get that?

$1 + \dfrac{1}{3} + \dfrac{1}{4} = \dfrac{12}{12} + \dfrac{4}{12} + \dfrac{3}{12} = \dfrac{19}{12}$

This is nowhere near what you just said.  You need to be able to add fractions.

Please show me $\dfrac{1}{8} + \dfrac{1}{6}$.  Add them.

anonymous · Answer

I don't understand

anonymous · Answer

all I want is the answer, im confused. and I don't understand fractions and never will

tkhunny · Answer

Therein lies the problem.  Why do you have an algebra problem to add algebraic fractions when it appears you have no background in adding numerical fractions?

1) Find a common denominator.
2) Promote each term to the common denominator.
3) Sum the numerators over the common denominator.

$\dfrac{1}{8} + \dfrac{1}{6}$

Common Denominator: 24

$\dfrac{1}{8} + \dfrac{1}{6} = \dfrac{3}{24} + \dfrac{4}{24}$

Fractions promoted to the common denominator.

$\dfrac{3+4}{24} = \dfrac{7}{24}$

You need to be able to do this fluently.

Numerators summed and it is still over that same denominator.

tkhunny · Answer

If you do not understand fractions and never will, then you cannot do this problem. That is the best advice anyone can give you.