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State the domain of the function: f(x)=(x^2+1)/(x^2-3x)
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well there are restrictions in the denominator... can you identify them..?
0, obviously.
3, I'm thinking.
Yes, three and nine.
Oops, sorry. Zero and three, I mean.
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there are only 2...0 and 3 \[x^2 - 3x = x(x - 3)\] so the domain is all real x except.... x = 0 and x = 3
Yes, I was just thinking that when you started replying Thank you so much. Sometimes it helps just to have someone work through it with you.
glad to help
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