Question

Can someone show me how to do: (8x + 2y)(5x - 4y)?

Answer 1

I WILL!

Answer 2

Thank you.

Answer 3

okay so first what we wanna do is 8x*5x

Answer 4

40x.

Answer 5

Then 8x times -4y, correct?

Answer 6

yes but instead of 40x it would be \[40x^2\]

Answer 7

Oh! Okay. That's probably why I got it wrong. 8x times -4y equals -32xy, then you do 2y times 5x, which equals 10xy. Lastly, 2y times - 4y which equals - 8y. Then you combine terms.

Answer 8

yes but remember the 8y should be\[8y^2\] because when you multiply two variables that are the same, you give it an exponent... so if it was x*x*x it would be \[x^3\]

Answer 9

so you end with \[40x^2-22xy+8y^2\]

Answer 10

Thank you for your help!

Answer 11

you're welcome!

Answer 12

Could you help me with one more problem? If you don't mind.

Answer 13

sure!

Answer 14

Thank you. The problem is: (3x^2 + 2) + 4(x - 2)^2.

Answer 15

I know first you do: (x - 2)^2 = (x - 2)(x - 2) = x^2 - 2x - 2x + 4.

Answer 16

Simplified is x^2 - 4x^2 + 4.

Answer 17

this is what you should end with

Answer 18

Oh, okay. Thank you!

Answer 19

or at least im possative.... your explanation for simplifying is making me question myself

Answer 20

nevermind im right just had to make sure

Answer 21

Thanks again.

Answer 22

okay wait I didn't fallow order of operations... the answer should be 7x^2-16x+18

Answer 23

you were correct with the simplified x^2-4x+4
then add that o 3x^2 + 2 you get \[7x^2-16x+18\]
sorry about that truthfully sorry

Answer 24

No problem, thank you for your help.