Question

how many atoms of phosphorus are in 3.4 mol of copper(II) phosphate?

Answer 1

\[3.4 mol Cu_{(II)}(\frac{6.022x10^{23}}{1 mole Cu_{(II)}})\]

Can you work that out?

Answer 2

yes, i put that but it says its incorrect

Answer 3

1 mole of Copper II Phosphate has about 6.02E23 units of of Copper II Phosphate

1 unit of Copper II phosphate has 3 units of Cu and 2 units of Phosphate (PO4): CU3(PO4)2

1 unit of Phosphate has 1 atom of Phosphorus

3.4 mol * 6.02E23 * 2 *1 = ?

Answer 4

thank you!