Question

I am at my wits end with this problem.

Solve the system of equations.

2x + 4y + 3z = 6

3x + 5y + 6z = 3

2x + 3y + 4z = 8

The answer choice are
a. (x= 63, y= -18, z= -16)
b. (x= 65, y= -20, z= -14)
c. (x= 62, y= -17, z= -15)
d. (x= 64, y= -19, z= -17)

Answer 1

i think it's A.

Answer 2

hold on don't do it yet okay

Answer 3

Okay I'll wait

Answer 4

you take 2 equations at a time, then cancel out 1 of the variables, in the end, you'll end up with 2 variables system of equations

2x + 4y + 3z = 6 <---- let's use this one

3x + 5y + 6z = 3 <----- and this one

2x + 3y + 4z = 8

let's cancel out by elimination

2x + 4y + 3z = 6 let's multiply this one by - 2
3x + 5y + 6z = 3



-4x - 8y - 6z = -12
3x + 5y + 6z = 3
--------------------
-x -3y + 0 = -9 <--- 1st 2 variable one


let's do the another 2

2x + 4y + 3z = 6 <--- let's use this one again

3x + 5y + 6z = 3

2x + 3y + 4z = 8 <--- and this one


2x + 4y + 3z = 6 <----- let's multiply this one by 4
2x + 3y + 4z = 8 <---- let's multiply this one by - 3


8x + 16y + 12z = 24
-6x - 9y - 12z = -24
-------------------------
2x + 7y + 0 = 0 <---- 2nd 2 variable one

Answer 5

Yes but I need the solutions. I can get it down to where I eliminate variables but none of my answers make sense.

Answer 6

\(\bf -x -3y + 0 = -9 \\
2x + 7y + 0 = 0\\\quad \\\quad \\
-x-3y=-9\\
2x+7y = 0 \)

then solve it like you'd any 2 variable system of equations

Answer 7

woops, need to dash

Answer 8

Thank you sooo much!

Answer 9

i am still here i will try

Answer 10

dam it this is hard i will still try it's not A

Answer 11

Idk it does not work i tryed i did my best i could not find it

Answer 12

i am sorry about this when S17 gets on he would be able to help @S17

Answer 13

sorry clan member i could not find it ^---^

Answer 14

@campbell_st help would you please we can not find it out

Answer 15

well I wouldn't solve anything, I'd just substitute

solution 1

x = 63, y = -18, z = -16

substitute into the 1st equation

2(63) + 4(-18) + 3(-16) = 6 true

so test this on the 2nd equation

3x + 5y+ 6z = 3

3(63) + 5(-18) + 6(-16) = 3 true so try it on the 3rd equation

2x + 3y + 4z = 8

2(63) + 3(-18) + 4(-16) = 8

so the values x = 63, y = -18 and z = -16 is a solution to the system of equations.

Answer 16

did he help at all

Answer 17

so it would be A.