math help please
\[\frac{ 3 }{ 5 }\div \frac{ 2 }{10 }\]
\[\frac{ 3 }{ 4 }\div \frac{ 3 }{ 5 }\]
\[\frac{ 2 }{ 3 }\div \frac{ 1 }{ 4 }\]
To divide by a fraction, you multiply by the reciprocal. So first re-write the problem as multiplication by the reciprocal, then reduce by any common factors, and then multiply straight across the num'r and den'r.
I have the easiest way for you to do this.
Flip the 2/10 to 10/2 than multiply it straight across.
BAM.
I'll do one that is similar to yours, as an example: \(\Large \frac{ 2 }{ 5 }\div \frac{ 7 }{15 }=\frac{ 2 }{ 5 }\times \frac{ 15 }{7 }=\frac{ 2 }{ {\cancel5}_1 }\times \frac{ \cancel{15}^3 }{7 }=\frac{ 6 }{ 7 }\)
so you only have to make one a reciprocal ?
That's just what I said.... except that you should always reduce BEFORE you multiply. ALWAYS. Otherwise, you just have MORE to reduce afterwards, and it's harder to do so.
Yes, only the 2nd one gets changed to reciprocal.
And that's ONLY for division.
okay i think i understand now
Great :)
so the first one is 3?
@DebbieG
now i am confused on the 3/4 and 3/5 one...
OK, what did you try to do? Tell me where your confused.
When you change it to multiplication by the reciprocal, what do you have? what times what?
\[\frac{ 3 }{ 4 }\div \frac{ 3 }{ 5 }=\frac{ 3 }{ 4 }\times \frac{ 5 }{ 3 }\]
just multiply the 4 and 5 ?
well, first you can cancel a common factor, right?
the 3's?
And the, I'm not sure what you mean by "multiply the 4 and the 5"... that worries me, lol. You don't multiply 4*5. You multiply across the num'r, and across the den'r. RIGHT, cancel the 3's.
soo... if you cancel out the 3 you would be left with 4 and 5. " Sorry I am really bad at math lol
ohmygosh... i just realized i wrote down the wrong thing. It's \[\frac{ 3 }{ 4 }\div \frac{ 4 }{ ? }\]
4/5**
OK - so again, you re-write as multiplication by reciprocal. Nothing will cancel this time - that's ok. Then you must multiply across num'r, and multiply across den'r. The method is always the same, no matter what the numbers are. :)
so 15/16?
\[\Large \frac{ a }{ b }\div \frac{ c }{ d }=\frac{ a }{ b }\times \frac{ d }{ c }=\frac{ ad }{ bc }\]
Right!
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