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Mathematics 22 Online
OpenStudy (anonymous):

math help please

OpenStudy (anonymous):

\[\frac{ 3 }{ 5 }\div \frac{ 2 }{10 }\]

OpenStudy (anonymous):

\[\frac{ 3 }{ 4 }\div \frac{ 3 }{ 5 }\]

OpenStudy (anonymous):

\[\frac{ 2 }{ 3 }\div \frac{ 1 }{ 4 }\]

OpenStudy (debbieg):

To divide by a fraction, you multiply by the reciprocal. So first re-write the problem as multiplication by the reciprocal, then reduce by any common factors, and then multiply straight across the num'r and den'r.

OpenStudy (anonymous):

I have the easiest way for you to do this.

OpenStudy (anonymous):

Flip the 2/10 to 10/2 than multiply it straight across.

OpenStudy (anonymous):

BAM.

OpenStudy (debbieg):

I'll do one that is similar to yours, as an example: \(\Large \frac{ 2 }{ 5 }\div \frac{ 7 }{15 }=\frac{ 2 }{ 5 }\times \frac{ 15 }{7 }=\frac{ 2 }{ {\cancel5}_1 }\times \frac{ \cancel{15}^3 }{7 }=\frac{ 6 }{ 7 }\)

OpenStudy (anonymous):

so you only have to make one a reciprocal ?

OpenStudy (debbieg):

That's just what I said.... except that you should always reduce BEFORE you multiply. ALWAYS. Otherwise, you just have MORE to reduce afterwards, and it's harder to do so.

OpenStudy (debbieg):

Yes, only the 2nd one gets changed to reciprocal.

OpenStudy (debbieg):

And that's ONLY for division.

OpenStudy (anonymous):

okay i think i understand now

OpenStudy (debbieg):

Great :)

OpenStudy (anonymous):

so the first one is 3?

OpenStudy (anonymous):

@DebbieG

OpenStudy (anonymous):

now i am confused on the 3/4 and 3/5 one...

OpenStudy (debbieg):

OK, what did you try to do? Tell me where your confused.

OpenStudy (debbieg):

When you change it to multiplication by the reciprocal, what do you have? what times what?

OpenStudy (anonymous):

\[\frac{ 3 }{ 4 }\div \frac{ 3 }{ 5 }=\frac{ 3 }{ 4 }\times \frac{ 5 }{ 3 }\]

OpenStudy (anonymous):

just multiply the 4 and 5 ?

OpenStudy (debbieg):

well, first you can cancel a common factor, right?

OpenStudy (anonymous):

the 3's?

OpenStudy (debbieg):

And the, I'm not sure what you mean by "multiply the 4 and the 5"... that worries me, lol. You don't multiply 4*5. You multiply across the num'r, and across the den'r. RIGHT, cancel the 3's.

OpenStudy (anonymous):

soo... if you cancel out the 3 you would be left with 4 and 5. " Sorry I am really bad at math lol

OpenStudy (anonymous):

ohmygosh... i just realized i wrote down the wrong thing. It's \[\frac{ 3 }{ 4 }\div \frac{ 4 }{ ? }\]

OpenStudy (anonymous):

4/5**

OpenStudy (debbieg):

OK - so again, you re-write as multiplication by reciprocal. Nothing will cancel this time - that's ok. Then you must multiply across num'r, and multiply across den'r. The method is always the same, no matter what the numbers are. :)

OpenStudy (anonymous):

so 15/16?

OpenStudy (debbieg):

\[\Large \frac{ a }{ b }\div \frac{ c }{ d }=\frac{ a }{ b }\times \frac{ d }{ c }=\frac{ ad }{ bc }\]

OpenStudy (debbieg):

Right!

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