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Chemistry 20 Online
OpenStudy (anonymous):

how many molecules are there in 68.56 kg of NaHCO3

thomaster (thomaster):

68.56 kg = 68560 grams now divide by the molar mass of NaHCO3 (84.007 g/mol) then multiply with Avogadro's number (6.0221413*10^23)

OpenStudy (anonymous):

Very nice, Thanks!!

thomaster (thomaster):

No problem :)

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