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OpenStudy (anonymous):
how many molecules are there in 68.56 kg of NaHCO3
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thomaster (thomaster):
68.56 kg = 68560 grams now divide by the molar mass of NaHCO3 (84.007 g/mol) then multiply with Avogadro's number (6.0221413*10^23)
OpenStudy (anonymous):
Very nice, Thanks!!
thomaster (thomaster):
No problem :)
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