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OpenStudy (anonymous):
\[|a+bi|=\sqrt{a^2+b^2}\]
OpenStudy (anonymous):
forget negative numbers, forget \(i\) just compute \(\sqrt{a^2+b^2}\) with
\[a=4,b=2\]
OpenStudy (anonymous):
what about the imaginary numbers though?
OpenStudy (anonymous):
what about them?
OpenStudy (anonymous):
like i said, ignore all minus signs and the \(i\)
the absolute value is a positive real number, the distance that your complex number is from the origin
by pythagoras, it is \(\sqrt{a^2+b^2}\)
i can draw a picture if you like
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OpenStudy (anonymous):
No it's fine, thankyou!
OpenStudy (anonymous):
|dw:1379642120389:dw|
OpenStudy (anonymous):
Would the absolute value of l 5 - i l be 5? & ohh okaay I got it :)
OpenStudy (anonymous):
@satellite73
OpenStudy (anonymous):
no no not 5
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OpenStudy (anonymous):
it is
\[\sqrt{5^2+1^2}=\sqrt{26}\]
OpenStudy (anonymous):
when i said "forget the \(i\) " i did not mean pretend it is not there, i meant don't include it in your calculations
this is the same as \(5-1i\) so you use 5 and 1