how do you graph a line with a slope of 2: passing through (-3,0)

Question

anonymous · Answer

put it in point slope form  y-0=2(x-(-3)
then it should be simplyfied to y-0=2(x+3)
then convert to slope intercept  y=2x+3 (because you distribute and add 0 to bth sides of the equation. 
then go to the point (0,3) and insert the slope (go up twice and to the right once)

anonymous · Answer

simply use the formula y-y1=m(x-x1) where m is the slope and (x1,y1) are the coordinates of the point

anonymous · Answer

@kmathsmiles55 how did you get the whole " y-0=2(x-(-3) " though?

anonymous · Answer

its an equation of a line.  point slope form. it's y-y1=m(x-x1)
the ones are little i cant find the button but its a real easy way to find what you're looking for becasue everything just kinda falls into place...you know what im saying?

anonymous · Answer

Ahhh. yeaah. I got it.

anonymous · Answer

WHOOOWWHH YAY!