Question

Solve the system using any algebraic method..

x-2y+4z= -19
2x+y-3z+14
3x+y + 2z=5

Answer 1

@campbell_st

Answer 2

looking at it the easiest to eliminate is y

double the 2nd equation and add it to the 1st equation

double the 3rd equation and add it to the 1st equation.

now you will have 2 equations in 2 unknowns.... you can use elimination or substitution to solve for x and z... when you get them substitute into any of the original equations to find y

hope this helps

Answer 3

can u pleasse show me how to do this prob....i know the directions but i still dont get it until i see how its done..

Answer 4

I'm guessing that
2x+y-3z+14 means
2x+y-3z = +14

Answer 5

yeah sorry

Answer 6

ok... double equation 2 and add to equation 1 to eliminate y

x - 2y + 4z = -19
+ 4x + 2y -6z = 28
------------------
5x -2z = 9


double equation 3 and add equation 1

x - 2y + 4z = -19
+ 6x + 2y + 4z = 10
--------------------
7x + 8z = -9

so now you need to solve

5x -2z = 9
7x + 8z = -9


so multiply the 1st equation by 4 and add to the 2nd equation, this will eliminate z

20x - 8z = 36
+ 7x + 8z = -9
-----------------
27x = 27

solve for x

hope this make sense

Answer 7

i alsoneed to find y and z

Answer 8

ok... if you know x to find z subsitute it into either of the equations that only contain x and z...

e.g. 5x -2z = 9

then when you get z... substitute x and z into any of the original equations to find y

Answer 9

i got 1,1.-2

Answer 10

I think you need to go and recheck y.

Answer 11

One of those ('y') is incorrect.

Answer 12

y=6?

Answer 13

thats correct,

Answer 14

ok i have another one please

x-y+z=5
2y+3z=14
=3y+2z=5

Answer 15

sure... what do you suggest.. as the 1st step

Answer 16

is the last equation

-3y +2z = 5

Answer 17

yes