∫[\x^2/(-x^3+x^2+x-1)\]

Question

psymon · Answer

Factor the denominator and then try partial fractions?

anonymous · Answer

is it possible [\(x^2/-x^3)+(x^2/x^2)+(x^2/x)+(x^2)\] ??

psymon · Answer

No, you cant legally do that. You can make a fraction for each termin the numerator, but NOT for each term in the denominator. The denominator must remain in tact.

psymon · Answer

If your problem was the opposite and you had the cubic in the numerator then yes, you could split it up, btu in this case we cannto, you must always have the whole denominator in tact.

anonymous · Answer

right. !! i have no idea, how to do this integration,

psymon · Answer

Do you know how to factor the bottom like I suggested?

anonymous · Answer

i tried x^2

psymon · Answer

Tried x^2 what?

anonymous · Answer

i think im just really stupid right now

psymon · Answer

well, just worry abotu -x^3 + x^2 + x - 1 and see if you can factor it. it will factor cleanly.

anonymous · Answer

-(x^3-x^2)+(x-1) , -x^2(x-1)+(x-1) , then x^2/((-x^2+1)(x-1))

psymon · Answer

You can do a slight bit more with the bottom to factor it.