Find the products AB and BA to determine whether B is the multiplicative inverse of A.
A=|dw:1379659053586:dw|
B=|dw:1379659103122:dw|
A. B = A-1 B. B ≠ A-1
Do you know how to do matrix multiplication?
And do you know what the answer must be for B to be A's multiplicative inverse?
a little bit not good at all.
& no i dont know what the answer must be
\[\left[\begin{matrix}A11&A12&A13\\A21&A22&A23 \\ A31&A32 &A33\end{matrix}\right].\left[\begin{matrix}B11&B12&B13\\B21&B22&B23 \\ B31&B32 &B33\end{matrix}\right]=\left[\begin{matrix}C11&C12&C13\\C21&C22&C23 \\ C31&C32 &C33\end{matrix}\right]\] A11 is matrix A row 1, column 1, A22 is matrix A row 2 column 2. You with me?
yea so far
C11 = A11*B11 + A12*B21 + A13*B31 That's the sum of the products of Row 1 of matrix A and Column 1 of B to give you C11. C12 = A11*B12 + A12*B22 + A13*B32 That's the sum of the products of Row 1 of matrix A and Column 2 of B to give you C12. For each member of C you just take not it's position then you sum the products of it's equivalent Row in A and the equivalent column in B. C32 = Row 3 of A and Column 2 of B.
That should be: For each member of C you just take NOTE OF it's position then you sum the products of it's equivalent Row in A and the equivalent column in B.
okay now im getting a little confused
\[\left[\begin{matrix}.&.&.\\A21&A22&A23 \\ .&. &.\end{matrix}\right].\left[\begin{matrix}.&.&B13\\.&.&B23 \\ .&. &B33\end{matrix}\right]=\left[\begin{matrix}.&.&.\\.&.&C23 \\ .&. &.\end{matrix}\right]\] C23 = A21*B13 + A22*B23 + A23*B33 I dunno if that makes it more clear.
It can get confusing I know. Took me a while to get this. Each member of C must be done the same way.
yea it does but were not doing my problem.
Yes we are What is 1*1 + 0*(-1) + 0*0? I'm trying to show you how to do it. It's difficult to explain using just 0s and 1s.
oh lol .. its okay but 1!
I'm hoping you can do it yourself now as I need to get back to work. Sorry.
nah ill just get the help tomo
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