Question

If I would solve for x


4^2x +1 = 8 ^ x + 5

then it would be ,

2 ^ 2(2x + 1 ) = 2 ^ 3 ( x + 5)

since we have same base,

4x + 2 = 3x +15

x = 13

Is this correct?

Answer 1

\(\large \color{Red}{\checkmark}\)

Answer 2

Thanks :) @ganeshie8 :))

Answer 3

np :) good job !!!

Answer 4

more brackets world make it clearer

Answer 5

sorry to confuse you :)

Answer 6

one way to check is to sub your soltion back into the origional equation
x=13 → 4^(2x +1) = 8 ^ (x + 5)

4^(2*13 +1) = 8 ^ (13 + 5)
4^(27) = 8 ^ (18)
2^54 = 2^54

Answer 7

I see, thanks :)

Answer 8

good work