The point P(2,9) lies on the curve y=x^2+x+3. If Q is the point (x,x^2+x+3), find the slope of the secant line PQ for the following values of x.
If x=2.1, the slope of PQ is:

Question

The point P(2,9) lies on the curve y=x^2+x+3. If Q is the point (x,x^2+x+3), find the slope of the secant line PQ for the following values of x. 
If x=2.1, the slope of PQ is:

anonymous · Answer

put value of x  to get coordinate of point Q and now as you have 2 point P and Q  so you can get slope of line passing through P and Q

anonymous · Answer

P=(2,9) Q=(2.1,9.51).  now how do I find the slope of the secant line? is it the same formula as finding the slope of a tangent line?

anonymous · Answer

no boy just slope =y2-y1/X2-X1 
x1,y1 coordinates of p
and x2,y2 coordinates of q

anonymous · Answer

Cool. Thank you very much. I got an answer of 5.1 I really appreciate it.

anonymous · Answer

its k bro.. you are most welcome