Question

I NEED HELP. PLEASE?? What is the value for x in the proportion http://learn.flvs.net/webdav/assessment_images/educator_algebra1_v14/10_19_44.jpg

Answer 1

Post an image, the link can not be followed in this form.

Answer 2

alright

Answer 3

hold on

Answer 4

You can use cross product,
\[\frac{x+8}{5x-2}=\frac{3}{8}\Rightarrow 3(5x-2)=8(x+8)\Rightarrow15x-6=8x+64\Rightarrow7x=70\Rightarrow x=10\]

Answer 5

wo i understand i just dint undertsnd the order, thanks alot

Answer 6

;)

Answer 7

can you help me with one more?

Answer 8

Ok

Answer 9

alrigh this is the problem...Assuming x > 0, what is the simplified fraction form for

Answer 10

wrong picture hold on

Answer 11

\[\frac{15x\sqrt{3}}{\sqrt{25\cdot x^2\cdot3}}=\frac{15x\sqrt{3}}{\sqrt{(5x)^23}}=\frac{15x\sqrt{3}}{5x\sqrt{3}}=3\]

Answer 12

alright... thanks do you mind doing one more? please

Answer 13

Ok ;)

Answer 14

Assuming x > 0, which of these expressions is equivalent to

Answer 15

\[11\sqrt{245x^3}+9\sqrt{45x^3}=11\sqrt{5\cdot7^2\cdot x^3}+9\sqrt{5\cdot 3^2 x^3}=11\sqrt{5\cdot(7x)^2\cdot x}+9\sqrt{5\cdot (3x)^2 x}=\\
=11\cdot7x\sqrt{5\cdot x}+9\cdot 3x\sqrt{5x}=77x\sqrt{5x}+27x\sqrt{5x}=104x\sqrt{5x}\]

Answer 16

wow alright thanks man

Answer 17

Hope it helps ;)

Answer 18

it does, so like i have a couple more i need help with if you are willing?

Answer 19

Ok, no problem ;)

Answer 20

alright
Which equation represents the line passing through the points (3, 2) and (−9, 6)?

x − 3y = 9

x + 3y = 9

3x − y = −9

3x + y = 9

Answer 21

As the line must pass trough the two points, then we have to calculate the slope,
\[y=mx+n\\
(x_1,y_1)=(-9,6)\\
(x_0,y_0)=(3,2)\\
m=\frac{y_1-y_0}{x_1-x_0}=\frac{4}{-12}=-\frac{1}{3}\]
So the x must be multiplied by 1/3 when the equation is expressed in the form y=mx+n. Only the first two satisfy this condition. But now we have to calculate then n. Until now our equation is,
\[y=-\frac{1}{3}x+n\]Now use any of the points they give you to calculate n.
\[2=-\frac{1}{3}3+n\Rightarrow n=3\]
So,
\[y=-\frac{1}{3}x+3\Rightarrow x+3y=9\]

Answer 22

wow how do i give you a medal?

Answer 23

alright one more question i think
Which ratio represents the area of the smaller rectangle compared to the area of the larger rectangle? (Figure not drawn to scale).

Answer 24

As you wish, and only if what I wrote helps you. For the problem, you must equate the sides that have a similiar form,
\[\frac{2x}{x}=\frac{x^2+5x+6}{x+2}\Rightarrow2=\frac{(x+2)(x+3)}{x+2}\Rightarrow2=x+3\Rightarrow x=-1\]

Answer 25

It is a little strange that they give you a problem with this solution, but it is what it can be deduced from the graph. Although negative measures are not physical.

Answer 26

thanks for all your help.. i want to give you one but idk how to

Answer 27

To give a medal (for other cases not only mine) you must choose the "best response", or click in the blue button "best response". ;)

Answer 28

wait i just relized what you did didnt match the answers that were given to me.

Answer 29

2x(x + 3) the last choice

Answer 30

oh okay thanks man you have a good one. i really appreciated all your help

Answer 31

Well, one moment, I put it better

Answer 32

Small rectangle area,
\[A_1=x(x+2)\]
Big rectangle area,
\[A_2=2x(x^2+5x+6)\]
Ratio between the smaller and the big,
\[A_1/A_2=\frac{x(x+2)}{2x(x^2+5x+6)}=\frac{x(x+2)}{2x(x+2)(x+3)}=\frac{1}{2(x+3)}\]
I didn't read the part of the "ratio between areas" and wrote the ratio between sides. Now it is ok.

Answer 33

alright :D