Question

6-3i/5+8i

Answer 1

\[\frac{ a+bi }{ a-bi } = \frac{ a+bi }{ a-bi }\times \frac{ a+bi }{ a+bi }\]

Answer 2

simply multiply by 1 in another form

5 - 8i/5-8i

this will allow the denominator to be a rational number

and i^2 = -1

Answer 3

(6-3i)/(5+8i)*(5-8i/5-8i)
=(6-3i)(5-8i)/[25-64(-1)]
=[30-48i-15i+24i^2]/98
=[30-36i-24]/98
=[6-36i]/98