Olivia tossed two fair two-sided coins. In a game, she earns 4 points if exactly one coin lands on heads and 6 points if both coins land on heads. If points are not earned for tails, what is the expected value of the points earned? (1 point) CE_3 and 1 over 3_img CE_3 1/2 5 6
P(H, T or T, H) = 1/2 P(H, H) = 1/4 The Expected Value = P(H,T or T, H) x 4 + P(H, H) x 6
I dont get it :(
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the expected return is the probability of the event multiplied by the points available so in tossing 2 fair coins what is the probability of 2 heads? P(H, H) =
I know the options... and one of them is the answer... its about trying to help you understand... expected value
do you need a tree diagram to show the sample space...?
is it 4,, but it is not the anser?
ok please
its not 4.... start with the basics... |dw:1379712970154:dw| use the diagram to get the probabilities
the sample space has 4 outcomes how many Head, Head outcomes are in the sample space..?
two?
The outcome you need is Head on the 1st coin and Head on the 2nd coin. How many ways does that happen?
two
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four?
no still not right... there are 4 possible outcomes and only 1 way to get a head on the 1st coin and Head on the 2nd coin |dw:1379713387644:dw| so the probability is P(Head, Head) = 1/4 does that make sense
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