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Mathematics 18 Online
OpenStudy (zuha):

Olivia tossed two fair two-sided coins. In a game, she earns 4 points if exactly one coin lands on heads and 6 points if both coins land on heads. If points are not earned for tails, what is the expected value of the points earned? (1 point) CE_3 and 1 over 3_img CE_3 1/2 5 6

OpenStudy (campbell_st):

P(H, T or T, H) = 1/2 P(H, H) = 1/4 The Expected Value = P(H,T or T, H) x 4 + P(H, H) x 6

OpenStudy (zuha):

I dont get it :(

OpenStudy (zuha):

|dw:1379712413585:dw|

OpenStudy (campbell_st):

the expected return is the probability of the event multiplied by the points available so in tossing 2 fair coins what is the probability of 2 heads? P(H, H) =

OpenStudy (campbell_st):

I know the options... and one of them is the answer... its about trying to help you understand... expected value

OpenStudy (campbell_st):

do you need a tree diagram to show the sample space...?

OpenStudy (zuha):

is it 4,, but it is not the anser?

OpenStudy (zuha):

ok please

OpenStudy (campbell_st):

its not 4.... start with the basics... |dw:1379712970154:dw| use the diagram to get the probabilities

OpenStudy (campbell_st):

the sample space has 4 outcomes how many Head, Head outcomes are in the sample space..?

OpenStudy (zuha):

two?

OpenStudy (campbell_st):

The outcome you need is Head on the 1st coin and Head on the 2nd coin. How many ways does that happen?

OpenStudy (zuha):

two

OpenStudy (campbell_st):

|dw:1379713246906:dw|

OpenStudy (zuha):

four?

OpenStudy (campbell_st):

no still not right... there are 4 possible outcomes and only 1 way to get a head on the 1st coin and Head on the 2nd coin |dw:1379713387644:dw| so the probability is P(Head, Head) = 1/4 does that make sense

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