Max observes the zoo and the library from a helicopter flying at a height of feet above the ground, as shown below. What is the distance between the zoo and the library? a. 400 feet b. 200 feet c. 600 feet d. 800 feet
You need to find the bottom legs of those two triangles. You trig relations, in this case tangent, to do so. Can you take it from here?
Use* not You
I did it i just need to see if my answer is right what did you get? i got b
Not quite. Give me the equation you use for one of the legs.
I'll walk you through this one. I'm calling the distance from G to the zoo x1, and G to the library x2. So we have that\[\tan(\pi/6)=\frac{ 200\sqrt{3} }{ x _{2} }\] and \[\tan(\pi/3)=\frac{ 200\sqrt{3} }{ x _{1} }\] from trig relations. Solving for x2 we get\[x _{2}=\frac{ 200\sqrt{3} }{\tan(\pi/6)}=\frac{ 200\sqrt{3} }{\frac{ 1 }{ \sqrt{3} }}=600\] Solving for x1 we get\[x _{1}=\frac{ 200\sqrt{3} }{ \tan(\pi/3) }=\frac{ 200\sqrt{3} }{ \sqrt{3} }=200\] So the distance between the zoo and the library is\[x _{2}-x _{1}=600-200=400\] So the answer is 400.
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