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How much heat energy is needed to raise the temperature of a 28 g sample of aluminum from 22.4°C to 87.1°C? Refer to Table 17-1 for the specific heat of aluminum. http://www.webassign.net/dmwc1/17-1tab.gif
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You must use the formula, \[Q=m\cdot c\cdot \Delta T\]
and what does each variable in that represent?
Q is the heat energy the answer for, m is the mass in grams, c is the specific heat from the table for the aluminium, and T is the variation of temperature in Kelvins.
Do you understand how to apply?
so 28 X 64.7 X 0.897?
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Perfect. The result is in Joule, don't forget to specify it in the solution.
thanks so much man! big help! so would the final answer be 1652.0052 J
beccause what about sigfigs
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