Question

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Answer 1

I don't think order matters, but there is one special seat (the jury foreman) usually, so I'm not entirely sure

Answer 2

Let's assume that order doesn't matter

so that would mean there are 22 C 14 = (22!)/(14!*(22-14)!) = 319,770 different ways to do this

I'm using 14 instead of 12 because there are 2 alternates

Answer 3

@jim_thompson5910 i just checked its not the right answer :$

Answer 4

hmm ok, let me think

Answer 5

it could possibly be

(22 C 12)*(10 C 2)

you would have to compute that using the formula

n C r = (n!)/(r!*(n-r)!)

to get a single number

Answer 6

@jim_thompson5910 a very similar question was 12 jurors and 2 alternates can be chosen from a pool of 17 prospective jurors and they asnwered it with C(17,12)XC(5,2)...i was confused on how they get the C(5,2) and why it won't work for my question..

Answer 7

well once you choose 12 people, you have 17-12 = 5 people left over to choose for alternates

Answer 8

so that's how I got 10 (22 - 12 = 10)

Answer 9

ohhh i see so for my qustion the answer would be 22,099,070?

Answer 10

yes

Answer 11

oh okay i get it now...thanks so much!!!

Answer 12

you're welcome