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Mathematics 20 Online
OpenStudy (anonymous):

How to differentiate f(x)=sinh^3xcosh^2x?

OpenStudy (john_es):

Use product rule and chain rule, \[(\sinh^3x)'\cosh^2x+\sinh^3x(\cosh^2x)'=\\ =3\sinh^2x\cosh x\cosh^2 x+\sinh^3 x2\cosh x\sinh x=\\ =3\sinh^2x\cosh^3 x+2\sinh^4\cosh x\]

OpenStudy (anonymous):

thank you!

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