If f(x) = (4/(x-2)) find f'(4) Use this to find the equation of the tangent line to the curve y = \frac {4}{x- 2 } at the point ( 4 , 2.00000 ). The equation of this tangent line can be written in the form y = mx+b where m is: and where b is:
Tell me what you think you should do?
\[\Large f(x) = \frac4{x-2}\]
Yes, but @MG757983 what is the significance of f '(4)? Can you tell me?
i figured out how to get f'(4) which is -1 and now i am confused on how to continue
i actually got it now thank you for your help!!!
Yes! Hence that is the slope of the tangent at the point (4, 2). You also have the x and y-coordinate of the point. Hence if you have the slope of the line, and a point on the line, how do you find the equation of the line?
Okay!
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